Optimal. Leaf size=51 \[ \frac{2 e^{4 i a}}{x^2+e^{2 i a}}+2 e^{2 i a} \log \left (x^2+e^{2 i a}\right )-\frac{x^2}{2} \]
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Rubi [F] time = 0.0318918, antiderivative size = 0, normalized size of antiderivative = 0., number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0., Rules used = {} \[ \int x \tan ^2(a+i \log (x)) \, dx \]
Verification is Not applicable to the result.
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Rubi steps
\begin{align*} \int x \tan ^2(a+i \log (x)) \, dx &=\int x \tan ^2(a+i \log (x)) \, dx\\ \end{align*}
Mathematica [B] time = 0.113743, size = 135, normalized size = 2.65 \[ \cos (2 a) \log \left (2 x^2 \cos (2 a)+x^4+1\right )+\frac{2 \cos (3 a)+2 i \sin (3 a)}{\left (x^2+1\right ) \cos (a)-i \left (x^2-1\right ) \sin (a)}+i \sin (2 a) \log \left (2 x^2 \cos (2 a)+x^4+1\right )+2 i \cos (2 a) \tan ^{-1}\left (\frac{\left (x^2+1\right ) \cot (a)}{x^2-1}\right )-2 \sin (2 a) \tan ^{-1}\left (\frac{\left (x^2+1\right ) \cot (a)}{x^2-1}\right )-\frac{x^2}{2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.072, size = 50, normalized size = 1. \begin{align*} -{\frac{5\,{x}^{2}}{2}}+2\,{\frac{{x}^{2}}{ \left ({{\rm e}^{i \left ( a+i\ln \left ( x \right ) \right ) }} \right ) ^{2}+1}}+2\, \left ({{\rm e}^{ia}} \right ) ^{2}\ln \left ( \left ({{\rm e}^{ia}} \right ) ^{2}+{x}^{2} \right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.02712, size = 261, normalized size = 5.12 \begin{align*} -\frac{x^{4} +{\left (4 \,{\left (-i \, \cos \left (2 \, a\right ) + \sin \left (2 \, a\right )\right )} \arctan \left (\sin \left (2 \, a\right ), x^{2} + \cos \left (2 \, a\right )\right ) + \cos \left (2 \, a\right ) + i \, \sin \left (2 \, a\right )\right )} x^{2} -{\left (4 i \, \cos \left (2 \, a\right )^{2} - 8 \, \cos \left (2 \, a\right ) \sin \left (2 \, a\right ) - 4 i \, \sin \left (2 \, a\right )^{2}\right )} \arctan \left (\sin \left (2 \, a\right ), x^{2} + \cos \left (2 \, a\right )\right ) -{\left (x^{2}{\left (2 \, \cos \left (2 \, a\right ) + 2 i \, \sin \left (2 \, a\right )\right )} + 2 \, \cos \left (2 \, a\right )^{2} + 4 i \, \cos \left (2 \, a\right ) \sin \left (2 \, a\right ) - 2 \, \sin \left (2 \, a\right )^{2}\right )} \log \left (x^{4} + 2 \, x^{2} \cos \left (2 \, a\right ) + \cos \left (2 \, a\right )^{2} + \sin \left (2 \, a\right )^{2}\right ) - 4 \, \cos \left (4 \, a\right ) - 4 i \, \sin \left (4 \, a\right )}{2 \, x^{2} + 2 \, \cos \left (2 \, a\right ) + 2 i \, \sin \left (2 \, a\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{2 \, x^{2} +{\left (e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 1\right )}{\rm integral}\left (-\frac{x e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 5 \, x}{e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 1}, x\right )}{e^{\left (2 i \, a - 2 \, \log \left (x\right )\right )} + 1} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.742233, size = 42, normalized size = 0.82 \begin{align*} - \frac{x^{2}}{2} + 2 e^{2 i a} \log{\left (x^{2} + e^{2 i a} \right )} + \frac{2 e^{4 i a}}{x^{2} + e^{2 i a}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.28563, size = 298, normalized size = 5.84 \begin{align*} -\frac{x^{4}}{2 \,{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )}} + \frac{2 \, x^{2} e^{\left (2 i \, a\right )} \log \left (x^{2} + e^{\left (2 i \, a\right )}\right )}{x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}} - \frac{5 \, x^{2} e^{\left (2 i \, a\right )}}{2 \,{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )}} + \frac{4 \, e^{\left (4 i \, a\right )} \log \left (x^{2} + e^{\left (2 i \, a\right )}\right )}{x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}} - \frac{3 \, e^{\left (4 i \, a\right )}}{2 \,{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )}} + \frac{2 \, e^{\left (6 i \, a\right )} \log \left (x^{2} + e^{\left (2 i \, a\right )}\right )}{{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )} x^{2}} + \frac{e^{\left (6 i \, a\right )}}{2 \,{\left (x^{2} + \frac{e^{\left (4 i \, a\right )}}{x^{2}} + 2 \, e^{\left (2 i \, a\right )}\right )} x^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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